Tugas Metode Numerik Pendidikan Matematika UMT

1. 1.1 Barisan Fibonacci
METODE NUMERIK FIBONACCI
Amelia Noviasari 1384202071
Denny Hardi 1384202110
Mona Yulinda Santika 1384202115
Risti Apriani Dewi 1384202141
Rudi Alviansyah 1384202100
March 11, 2016
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

2. 1.1 Barisan Fibonacci
Barisan Fibonacci
1 1.1 Barisan Fibonacci
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

3. 1.1 Barisan Fibonacci
Definisi
Barisan f0, f1, f2, f3, ..., fn − 2, fn − 1, fn disebut Fibonacci jika untuk
f0 = 1, f1 = 0 + f0, f2 = f0 + f1,f3 = f2 + f1,...,fn = fn − 2 + fn − 1
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

4. 1.1 Barisan Fibonacci
Definisi
Barisan f0, f1, f2, f3, ..., fn − 2, fn − 1, fn disebut Fibonacci jika untuk
f0 = 1, f1 = 0 + f0, f2 = f0 + f1,f3 = f2 + f1,...,fn = fn − 2 + fn − 1
contoh barisan fibonacci
1, 1, 2, 3, 5, 8, 13, 21, 34, 55, ...
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

5. 1.1 Barisan Fibonacci
Algoritma nilai optimal dengan Metode Fibonacci
Dicari nilai n terkecil
1
Fn+1
<
2δ
L
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

6. 1.1 Barisan Fibonacci
Algoritma nilai optimal dengan Metode Fibonacci
Dicari nilai n terkecil
1
Fn+1
<
2δ
L
dibentuk
L0 = Fn+1Ln
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

7. 1.1 Barisan Fibonacci
Algoritma nilai optimal dengan Metode Fibonacci
Dicari nilai n terkecil
1
Fn+1
<
2δ
L
dibentuk
L0 = Fn+1Ln
dibentuk
λi = ai +
F(n+1)−i−1
F(n+1)−i+1
(bi − ai )
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

8. 1.1 Barisan Fibonacci
lanjutan
dicari
µi = ai +
F(n+1)−i
F(n+1)−i+1
(bi − ai )
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

9. 1.1 Barisan Fibonacci
lanjutan
dicari
µi = ai +
F(n+1)−i
F(n+1)−i+1
(bi − ai )
jika
f (µi ) > f (λi )
ambil µi dan ai , masing-masing sebagai bi+1 dan ai+1
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

10. 1.1 Barisan Fibonacci
lanjutan
dicari
µi = ai +
F(n+1)−i
F(n+1)−i+1
(bi − ai )
jika
f (µi ) > f (λi )
ambil µi dan ai , masing-masing sebagai bi+1 dan ai+1
iterasi berhenti ketika bi − ai < 2δ
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

11. 1.1 Barisan Fibonacci
Soal
minimalkan
f (x) = 2x3
− 3x2
dengan δ = 0, 1 pada selang −2 <= x <= 3
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

12. 1.1 Barisan Fibonacci
Soal
minimalkan
f (x) = 2x3
− 3x2
dengan δ = 0, 1 pada selang −2 <= x <= 3
dengan cara analitik, diperoleh nilai x yang meminimalkan
f (x) adalah x = 1
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

13. 1.1 Barisan Fibonacci
Dicari nilai n terkecil
1
Fn+1
<
2δ
L
1
F7+1
<
2δ
5
1
34
<
1
25
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

14. 1.1 Barisan Fibonacci
Dicari nilai n terkecil
1
Fn+1
<
2δ
L
1
F7+1
<
2δ
5
1
34
<
1
25
dibentuk
L0 = Fn+1Ln
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

15. 1.1 Barisan Fibonacci
Dicari nilai n terkecil
1
Fn+1
<
2δ
L
1
F7+1
<
2δ
5
1
34
<
1
25
dibentuk
L0 = Fn+1Ln
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

16. 1.1 Barisan Fibonacci
Iterasi I
λ1 = a1 +
F(7+1)−1−1
F(7+1)−1+1
(b1 − a1)
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

17. 1.1 Barisan Fibonacci
Iterasi I
λ1 = a1 +
F(7+1)−1−1
F(7+1)−1+1
(b1 − a1)
λ1 = −2 +
F(6)
F(8)
(3 − (−2))
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

18. 1.1 Barisan Fibonacci
Iterasi I
λ1 = a1 +
F(7+1)−1−1
F(7+1)−1+1
(b1 − a1)
λ1 = −2 +
F(6)
F(8)
(3 − (−2))
λ1 = −2 +
13
34
(5)
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

19. 1.1 Barisan Fibonacci
Iterasi I
λ1 = a1 +
F(7+1)−1−1
F(7+1)−1+1
(b1 − a1)
λ1 = −2 +
F(6)
F(8)
(3 − (−2))
λ1 = −2 +
13
34
(5)
λ1 = −0, 088
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

20. 1.1 Barisan Fibonacci
lanjutan iterasi I
µ1 = a1 +
F(7+1)−1
F(7+1)−1+1
(b1 − a1)
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

21. 1.1 Barisan Fibonacci
lanjutan iterasi I
µ1 = a1 +
F(7+1)−1
F(7+1)−1+1
(b1 − a1)
µ1 = −2 +
F(7)
F(8)
(3 − (−2))
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

22. 1.1 Barisan Fibonacci
lanjutan iterasi I
µ1 = a1 +
F(7+1)−1
F(7+1)−1+1
(b1 − a1)
µ1 = −2 +
F(7)
F(8)
(3 − (−2))
µ1 = −2 +
21
34
(5)
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

23. 1.1 Barisan Fibonacci
lanjutan iterasi I
µ1 = a1 +
F(7+1)−1
F(7+1)−1+1
(b1 − a1)
µ1 = −2 +
F(7)
F(8)
(3 − (−2))
µ1 = −2 +
21
34
(5)
µ1 = 1, 088
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

24. 1.1 Barisan Fibonacci
lanjutan iterasi I
f (λ1) = 2λ1
3
− 3λ1
2
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

25. 1.1 Barisan Fibonacci
lanjutan iterasi I
f (λ1) = 2λ1
3
− 3λ1
2
f (λ1) = 2(−0, 088)3
− 3(−0, 088)2
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

26. 1.1 Barisan Fibonacci
lanjutan iterasi I
f (λ1) = 2λ1
3
− 3λ1
2
f (λ1) = 2(−0, 088)3
− 3(−0, 088)2
f (λ1) = −0, 001 − 0, 023
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

27. 1.1 Barisan Fibonacci
lanjutan iterasi I
f (λ1) = 2λ1
3
− 3λ1
2
f (λ1) = 2(−0, 088)3
− 3(−0, 088)2
f (λ1) = −0, 001 − 0, 023
f (λ1) = −0, 024
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

28. 1.1 Barisan Fibonacci
lanjutan iterasi I
f (µ1) = 2µ1
3
− 3µ1
2
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

29. 1.1 Barisan Fibonacci
lanjutan iterasi I
f (µ1) = 2µ1
3
− 3µ1
2
f (µ1) = 2(1, 088)3
− 3(1, 088)2
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

30. 1.1 Barisan Fibonacci
lanjutan iterasi I
f (µ1) = 2µ1
3
− 3µ1
2
f (µ1) = 2(1, 088)3
− 3(1, 088)2
f (µ1) = 2, 576 − 3, 551
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

31. 1.1 Barisan Fibonacci
lanjutan iterasi I
f (µ1) = 2µ1
3
− 3µ1
2
f (µ1) = 2(1, 088)3
− 3(1, 088)2
f (µ1) = 2, 576 − 3, 551
f (µ1) = −0, 975
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

32. 1.1 Barisan Fibonacci
lanjutan iterasi I
f (µ1) = 2µ1
3
− 3µ1
2
f (µ1) = 2(1, 088)3
− 3(1, 088)2
f (µ1) = 2, 576 − 3, 551
f (µ1) = −0, 975
f (λ1) > f (µ1)
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

33. 1.1 Barisan Fibonacci
lanjutan iterasi I
f (µ1) = 2µ1
3
− 3µ1
2
f (µ1) = 2(1, 088)3
− 3(1, 088)2
f (µ1) = 2, 576 − 3, 551
f (µ1) = −0, 975
f (λ1) > f (µ1)
λ1 = −0, 088(a2)
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

34. 1.1 Barisan Fibonacci
lanjutan iterasi I
f (µ1) = 2µ1
3
− 3µ1
2
f (µ1) = 2(1, 088)3
− 3(1, 088)2
f (µ1) = 2, 576 − 3, 551
f (µ1) = −0, 975
f (λ1) > f (µ1)
λ1 = −0, 088(a2)
b1 = 3(b2)
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

35. 1.1 Barisan Fibonacci
Iterasi II
λ2 = a2 +
F(7+1)−2−1
F(7+1)−2+1
(b2 − a2)
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

36. 1.1 Barisan Fibonacci
Iterasi II
λ2 = a2 +
F(7+1)−2−1
F(7+1)−2+1
(b2 − a2)
λ2 = −0, 088 +
F(5)
F(7)
(3 − (−0, 088))
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

37. 1.1 Barisan Fibonacci
Iterasi II
λ2 = a2 +
F(7+1)−2−1
F(7+1)−2+1
(b2 − a2)
λ2 = −0, 088 +
F(5)
F(7)
(3 − (−0, 088))
λ2 = −0, 088 +
8
21
(3, 088)
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

38. 1.1 Barisan Fibonacci
Iterasi II
λ2 = a2 +
F(7+1)−2−1
F(7+1)−2+1
(b2 − a2)
λ2 = −0, 088 +
F(5)
F(7)
(3 − (−0, 088))
λ2 = −0, 088 +
8
21
(3, 088)
λ2 = 1, 088
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

39. 1.1 Barisan Fibonacci
lanjutan iterasi II
µ2 = a2 +
F(7+1)−2
F(7+1)−2+1
(b2 − a2)
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

40. 1.1 Barisan Fibonacci
lanjutan iterasi II
µ2 = a2 +
F(7+1)−2
F(7+1)−2+1
(b2 − a2)
µ2 = −0, 088 +
F(6)
F(7)
(3 − (−0, 088))
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

41. 1.1 Barisan Fibonacci
lanjutan iterasi II
µ2 = a2 +
F(7+1)−2
F(7+1)−2+1
(b2 − a2)
µ2 = −0, 088 +
F(6)
F(7)
(3 − (−0, 088))
µ2 = −0, 088 +
13
21
(3, 088)
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

42. 1.1 Barisan Fibonacci
lanjutan iterasi II
µ2 = a2 +
F(7+1)−2
F(7+1)−2+1
(b2 − a2)
µ2 = −0, 088 +
F(6)
F(7)
(3 − (−0, 088))
µ2 = −0, 088 +
13
21
(3, 088)
µ2 = 1, 744
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

43. 1.1 Barisan Fibonacci
lanjutan iterasi II
f (λ2) = 2λ2
3
− 3λ2
2
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

44. 1.1 Barisan Fibonacci
lanjutan iterasi II
f (λ2) = 2λ2
3
− 3λ2
2
f (λ2) = 2(1, 088)3
− 3(1, 088)2
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

45. 1.1 Barisan Fibonacci
lanjutan iterasi II
f (λ2) = 2λ2
3
− 3λ2
2
f (λ2) = 2(1, 088)3
− 3(1, 088)2
f (λ2) = 2, 576 − 3, 551
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

46. 1.1 Barisan Fibonacci
lanjutan iterasi II
f (λ2) = 2λ2
3
− 3λ2
2
f (λ2) = 2(1, 088)3
− 3(1, 088)2
f (λ2) = 2, 576 − 3, 551
f (λ2) = −0, 975
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

47. 1.1 Barisan Fibonacci
lanjutan iterasi II
f (µ2) = 2µ2
3
− 3µ2
2
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

48. 1.1 Barisan Fibonacci
lanjutan iterasi II
f (µ2) = 2µ2
3
− 3µ2
2
f (µ2) = 2(1, 744)3
− 3(1, 744)2
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

49. 1.1 Barisan Fibonacci
lanjutan iterasi II
f (µ2) = 2µ2
3
− 3µ2
2
f (µ2) = 2(1, 744)3
− 3(1, 744)2
f (µ2) = 10, 609 − 9, 125
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

50. 1.1 Barisan Fibonacci
lanjutan iterasi II
f (µ2) = 2µ2
3
− 3µ2
2
f (µ2) = 2(1, 744)3
− 3(1, 744)2
f (µ2) = 10, 609 − 9, 125
f (µ2) = 1, 484
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

51. 1.1 Barisan Fibonacci
lanjutan iterasi II
f (µ2) = 2µ2
3
− 3µ2
2
f (µ2) = 2(1, 744)3
− 3(1, 744)2
f (µ2) = 10, 609 − 9, 125
f (µ2) = 1, 484
f (µ2) > f (λ2)
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

52. 1.1 Barisan Fibonacci
lanjutan iterasi II
f (µ2) = 2µ2
3
− 3µ2
2
f (µ2) = 2(1, 744)3
− 3(1, 744)2
f (µ2) = 10, 609 − 9, 125
f (µ2) = 1, 484
f (µ2) > f (λ2)
µ2 = −1, 744(b3)
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

53. 1.1 Barisan Fibonacci
lanjutan iterasi II
f (µ2) = 2µ2
3
− 3µ2
2
f (µ2) = 2(1, 744)3
− 3(1, 744)2
f (µ2) = 10, 609 − 9, 125
f (µ2) = 1, 484
f (µ2) > f (λ2)
µ2 = −1, 744(b3)
a2 = −0, 088(a3)
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

54. 1.1 Barisan Fibonacci
Iterasi III
λ3 = a3 +
F(7+1)−3−1
F(7+1)−3+1
(b3 − a3)
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

55. 1.1 Barisan Fibonacci
Iterasi III
λ3 = a3 +
F(7+1)−3−1
F(7+1)−3+1
(b3 − a3)
λ3 = −0, 088 +
F(4)
F(6)
(1, 744 − (−0, 088))
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

56. 1.1 Barisan Fibonacci
Iterasi III
λ3 = a3 +
F(7+1)−3−1
F(7+1)−3+1
(b3 − a3)
λ3 = −0, 088 +
F(4)
F(6)
(1, 744 − (−0, 088))
λ3 = −0, 088 +
5
13
(1, 832)
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

57. 1.1 Barisan Fibonacci
Iterasi III
λ3 = a3 +
F(7+1)−3−1
F(7+1)−3+1
(b3 − a3)
λ3 = −0, 088 +
F(4)
F(6)
(1, 744 − (−0, 088))
λ3 = −0, 088 +
5
13
(1, 832)
λ3 = −0, 617
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58. 1.1 Barisan Fibonacci
lanjutan iterasi III
µ3 = a3 +
F(7+1)−3
F(7+1)−3+1
(b3 − a3)
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59. 1.1 Barisan Fibonacci
lanjutan iterasi III
µ3 = a3 +
F(7+1)−3
F(7+1)−3+1
(b3 − a3)
µ3 = −0, 088 +
F(5)
F(6)
(1, 744 − (−0, 088))
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

60. 1.1 Barisan Fibonacci
lanjutan iterasi III
µ3 = a3 +
F(7+1)−3
F(7+1)−3+1
(b3 − a3)
µ3 = −0, 088 +
F(5)
F(6)
(1, 744 − (−0, 088))
µ3 = −0, 088 +
8
13
(1, 832)
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

61. 1.1 Barisan Fibonacci
lanjutan iterasi III
µ3 = a3 +
F(7+1)−3
F(7+1)−3+1
(b3 − a3)
µ3 = −0, 088 +
F(5)
F(6)
(1, 744 − (−0, 088))
µ3 = −0, 088 +
8
13
(1, 832)
µ3 = 1, 039
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

62. 1.1 Barisan Fibonacci
lanjutan iterasi III
f (λ3) = 2λ3
3
− 3λ3
2
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

63. 1.1 Barisan Fibonacci
lanjutan iterasi III
f (λ3) = 2λ3
3
− 3λ3
2
f (λ3) = 2(0, 617)3
− 3(0, 617)2
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

64. 1.1 Barisan Fibonacci
lanjutan iterasi III
f (λ3) = 2λ3
3
− 3λ3
2
f (λ3) = 2(0, 617)3
− 3(0, 617)2
f (λ3) = 0, 470 − 1, 142
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65. 1.1 Barisan Fibonacci
lanjutan iterasi III
f (λ3) = 2λ3
3
− 3λ3
2
f (λ3) = 2(0, 617)3
− 3(0, 617)2
f (λ3) = 0, 470 − 1, 142
f (λ3) = −0, 672
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66. 1.1 Barisan Fibonacci
lanjutan iterasi III
f (µ3) = 2µ3
3
− 3µ3
2
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

67. 1.1 Barisan Fibonacci
lanjutan iterasi III
f (µ3) = 2µ3
3
− 3µ3
2
f (µ3) = 2(1, 039)3
− 3(1, 039)2
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

68. 1.1 Barisan Fibonacci
lanjutan iterasi III
f (µ3) = 2µ3
3
− 3µ3
2
f (µ3) = 2(1, 039)3
− 3(1, 039)2
f (µ3) = 2, 243 − 3, 239
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

69. 1.1 Barisan Fibonacci
lanjutan iterasi III
f (µ3) = 2µ3
3
− 3µ3
2
f (µ3) = 2(1, 039)3
− 3(1, 039)2
f (µ3) = 2, 243 − 3, 239
f (µ3) = −1, 086
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

70. 1.1 Barisan Fibonacci
lanjutan iterasi III
f (µ3) = 2µ3
3
− 3µ3
2
f (µ3) = 2(1, 039)3
− 3(1, 039)2
f (µ3) = 2, 243 − 3, 239
f (µ3) = −1, 086
f (λ3) > f (µ3)
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

71. 1.1 Barisan Fibonacci
lanjutan iterasi III
f (µ3) = 2µ3
3
− 3µ3
2
f (µ3) = 2(1, 039)3
− 3(1, 039)2
f (µ3) = 2, 243 − 3, 239
f (µ3) = −1, 086
f (λ3) > f (µ3)
λ3 = 0, 617(a4)
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

72. 1.1 Barisan Fibonacci
lanjutan iterasi III
f (µ3) = 2µ3
3
− 3µ3
2
f (µ3) = 2(1, 039)3
− 3(1, 039)2
f (µ3) = 2, 243 − 3, 239
f (µ3) = −1, 086
f (λ3) > f (µ3)
λ3 = 0, 617(a4)
b3 = 1, 744(b4)
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

73. 1.1 Barisan Fibonacci
Tabel perhitungan dengan Metode Fibonacci
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74. 1.1 Barisan Fibonacci
x∗
= a8 +
b8 − a8
2
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

75. 1.1 Barisan Fibonacci
x∗
= a8 +
b8 − a8
2
x∗
= 1, 039 +
1, 180 − 1, 039
2
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI

76. 1.1 Barisan Fibonacci
x∗
= a8 +
b8 − a8
2
x∗
= 1, 039 +
1, 180 − 1, 039
2
x∗
= 1, 109
Amelia Noviasari 1384202071 Denny Hardi 1384202110 Mona Yulinda Santika 1384202115 Risti Apriani Dewi 1384202141 Rudi AMETODE NUMERIK FIBONACCI